Saturday, March 20, 2010

Electrostatic Motor

Electrostatic motor

Casey Rodgers

March 20, 2010

While looking through an old magazine on energy I wrote in my notes about a little corner in the last few pages of the magazine which was simply:

“A 300 foot antenna is ~2000V DC of electrostatic field of the earth at this height. This is switched across split field plates which alternately attract and repel an electrets disk causing it to spin.”

At first this wasn’t obvious how the disk could create torque if the electret was a uniform electric field. Now I see that the solution is to divide the disk in half with opposite polarizations so now the device looks something like this:

The generation of a resonant angular velocity involves using the existing electric field of the electret to counter-balance the electric field of the antennae relative to ground. I n other-words there is a capacitance in the aerial and a rotor force involved. By using a slip ring to create an AC then there will be a classic attract-repel rotor action. This works in powering a limited range of load depending on the strength of electric field of the electret. The first equation describes how the electric field (E) is related to the B-field in this case with a spinning rotor with velocity (v).

E= v × B [eq.1]

Force of Elecret = Force of magnetic pressure (displacement current force)

qE=(B^2)/(mu-not)*(area) [eq.2] q-charge (mu_not)-Permeability of free space

If this device (which by the above formula would be self regulating) load was built to take a mechanical load then a magnetic generator like the “phi” generator would be perfect for the job. This would then be excess AC energy that could be utilized within a certain range of load impedance.


1 comment:

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